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The electric field at a point near an infinite thin sheet of charged conductor is :(a) Eo o (b)1.olu(c) 2 60(a) zce, |
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Answer» e ▓█►─═ Ans : E = σ/2ε₀first understand what is difference between sheet and plate in electrostatic ?sheet => both side charge plate => one side charge here , MENTIONED sheet , then surely charge will appear in both side of conductor .now, Use the Gauss concept for finding electric FIELD .Let Q present in charged sheet conductor .because , I clearify that both side charge PRESENTS in sheet . so, each side charge share = Q/2 so, each side charge share = Q/2 now, Gauss formula, Φ = Qnet/2ε₀here , Qnet at one side = Q/2 also we know, Φ { electric flux near the surface of sheet } = E{electric field near the surface} × A { cross section Area of gaussian surface is chosen by us } so, EA = Q/2ε₀E = Q/2Aε₀= {Q/A}/2εwe know, Q/A = surface charge density = σwe know, Q/A = surface charge density = σE = σ/2ε₀hence, electric field at a point near an infinite sheet of charged conductor is σ/2ε₀ ═─◄█▓Hope it's helps you ✨ |
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