1.

The electric current in electric bulb is 22 mA. What is the charge flowing through the filament in 4s ?​

Answer»

Answer:

88 MC

Explanation:

Current-charge RELATIONSHIP is

Q = it

= 22 mA × 4 s

= 22 × 10^-3 A × 4 s

= 88 × 10^-3 As

= 88 × 10^-3 C

= 88 mC



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