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The electric current in electric bulb is 22 mA. What is the charge flowing through the filament in 4s ? |
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Answer» Answer: 88 MC Explanation: Current-charge RELATIONSHIP is Q = it = 22 mA × 4 s = 22 × 10^-3 A × 4 s = 88 × 10^-3 As = 88 × 10^-3 C = 88 mC |
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