The efficiency of an ideal gas with adiabatic exponent 'gamma' for the shown cyclic process would be

The efficiency of an ideal gas with adiabatic exponent 'gamma' for the

1.	The efficiency of an ideal gas with adiabatic exponent 'gamma' for the shown cyclic process would be
Answer» <P>`((2ln2-1))/(GAMMA//(gamma-1))` `((1-2ln2))/(gamma//(gamma-1))` `((2ln2+1))/(gamma//(gamma-1))` `((2ln2-1))/(gamma//(gamma+1))` Solution :`W_(BC)=PDeltaV=nRDeltaT=-nRT_(0)` `W_(CA)=+2nRT_(0)ln2` `DeltaQ_(BC)=nC_(p)DeltaT=(nRgammaT_(0))/(gamma-1)` HENCE, efficiency `((2ln2-1))/(gamma//(gamma-1))`