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The efficiency of a Carnot engine operating between temperatures 100 °C and -23°C will be. ​

Answer»

( 100 + 23 ) / 373 !Explanation:EFFICIENCY of Carnot engine is GIVEN by n = 1 = T2 / T1 = T1 - T2 / T1 _[i]Given, T1 = temperature of reservoir T1 = 100 + 237 = 373 KT2 = temperature of SINK T2 = -23 + 273 = 250 KSubstituting in Eq [i] we get, ∴ n = 373 - 250 / 373 = 123 / 373∴ n = 100 + 23 / 373



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