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The efficiency of a Carnot engine is 35.0%. What is the temperature of the cold reservoir if the temperature of the hot reservoir is 400 K?a. 140 Kb. 325 Kc. 260 Kd. 235 K |
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Answer» Correct option is (C) 260 K The efficiency of carnot engine \(\eta\) = 1 - \(\frac{T_2}{T_1}\) .35 = 1 - \(\frac{T_2}{400}\) \(\frac{T_2}{400}=1-0.35\) \(\frac{T_2}{400}=0.65\) T2 = \(\frac{0.65}{100}\times400\) T2 = 260 K |
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