1.

The efficiency of a Carnot engine is 35.0%. What is the temperature of the cold reservoir if the temperature of the hot reservoir is 400 K?a. 140 Kb. 325 Kc. 260 Kd. 235 K

Answer»

Correct option is (C) 260 K

The efficiency of carnot engine \(\eta\) = 1 - \(\frac{T_2}{T_1}\)

.35 = 1 - \(\frac{T_2}{400}\) 

\(\frac{T_2}{400}=1-0.35\) 

\(\frac{T_2}{400}=0.65\) 

T2 = \(\frac{0.65}{100}\times400\)

T2 = 260 K



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