1.

The earth's magnetic field at a place with zero declination is 3xx 10^(-4) T. The angle of dip at that place is 30^@. A conducting rod is kept is north south direction and is moved at a constant speed of 1 m/s towards east. The emf induced in the rod is ...... (The length of the rod is 10 cm.)

Answer»

`15muV`
`15mV`
0.15V
1.5V

Solution :
`vecl` and `vecv` are MUTUALLY perpendicular
`therefore veclxxvecv=lv hatn`, where `hatn` is unit VECTOR in the downward direction.
`hatn` makes an angle of `60^@` with `vecB`.
`therefore epsilon=vecB.(veclxxvecn)=vecB.lvhatn`
=Blv cos`theta`
=Blv cos `60^@`
`=3xx10^(-4)xx0.1xx1xx1/2`
`=0.15xx10^(-4)=15xx10^(-6)` V
`therefore epsilon=15muV`


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