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The earth is assumed to be a sphere of radius R. A platform is arranged at a height R from the surface of earth. The escape velocity of a body from this platform is fv, where v is its escape velocityfrom surfaceof the earth. The value of f is : |
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Answer» `(1)/(2)` `v=sqrt((2GM)/(R ))` If v. is escape velocity from the platform then Kinetic energy + Gravitational POTENTIAL energy = 0. `(1)/(2)mv.^(2)+(-(GMm)/(2R))=0 rArr v.= sqrt((GM)/(R ))=FV` `THEREFORE f=(v.)/(v)=(1)/(sqrt(2))`. Thus correct choice is (c ). |
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