The e.m.f. of the cell `Ti|Ti^(+)(0.001M)||Cu^(2+)(0.01M)|Cu` is 0.83V the emf of this cell could b e increased byA. increasing the concentration of `Ti^(+)` ionsB. increasing the concentration of `Cu^(2+)` ionsC. increasing the concentration of bothD. none of the above.

The e.m.f. of the cell `Ti|Ti^(+)(0.001M)||Cu^(2+)(0.01M)|Cu` is 0.83V

1.	The e.m.f. of the cell `Ti\|Ti^(+)(0.001M)\|\|Cu^(2+)(0.01M)\|Cu` is 0.83V the emf of this cell could b e increased byA. increasing the concentration of `Ti^(+)` ionsB. increasing the concentration of `Cu^(2+)` ionsC. increasing the concentration of bothD. none of the above.
Answer» Correct Answer - B `E_("cell")=E_("cell")^(@)+(0.059)/(n)"log"([Cu^(+2)])/([Ti^(+)]^(2))` Increasing conc. Of `Cu^(+2)` ions increases the emf.

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The e.m.f. of the cell `Ti|Ti^(+)(0.001M)||Cu^(2+)(0.01M)|Cu` is 0.83V the emf of this cell could b e increased byA. increasing the concentration of `Ti^(+)` ionsB. increasing the concentration of `Cu^(2+)` ionsC. increasing the concentration of bothD. none of the above.

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