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The drift velocity is 5V and the applied electric field intensity 20v/m what will be the mobility of charge carriers.(a) 100 m^2/ (vs)(b) 4 m^2/ (vs)(c) 15 m^2/ (vs)(d) 0.25 m^2/ (vs)I had been asked this question during an internship interview.Question is taken from Quantitative Theory of the P-N Diode Currents topic in chapter Semiconductor-Diode Characteristics of Electronic Devices & Circuits

Answer»

The correct CHOICE is (d) 0.25 m^2/ (vs)

The explanation: We KNOW that MOBILITY of charge carriers is drift velocity DIVIDE by applied electric field INTENSITY. Mobility = drift velocity / field intensity.



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