The distances covered by a particle thrownin a vertical plane, in hori

1.	The distances covered by a particle thrownin a vertical plane, in horizontaldirections at any instant of time x=3t and y=4t - 4t^2. The range of theparticle
Answer» Explanation: h= U sinQ t +1/2 gt^2 R= u cosQ t usinQ=4 - 1 u cosQ=3 -2 division of 1 and 2 tanQ= 4/3 Q = 53 u= (usinQ^2 + ucosQ^2) ^1/2 u= 5 R= u^2 sin2Q/g R= 3.34 m

The distances covered by a particle thrownin a vertical plane, in horizontaldirections at any instant of time x=3t and y=4t - 4t^2. The range of theparticle

Answer»

Explanation:

h= U sinQ t +1/2 gt^2

R= u cosQ t

usinQ=4 - 1

u cosQ=3 -2

division of 1 and 2

tanQ= 4/3

Q = 53

u= (usinQ^2 + ucosQ^2) ^1/2

u= 5

R= u^2 sin2Q/g

R= 3.34 m

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The distances covered by a particle thrownin a vertical plane, in horizontaldirections at any instant of time x=3t and y=4t - 4t^2. The range of theparticle ​

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The distances covered by a particle thrownin a vertical plane, in horizontaldirections at any instant of time x=3t and y=4t - 4t^2. The range of theparticle