1.

The distance covered by a particle moving along a straight line path with uniform acceleration is given by x=6+7t+10t

Answer»

,DIFFERENTIATE the given EQUATION w.r.t. t(time)….dx/dt=0+7+(2×10)t^2-1dx/dt=20t+7since,dx/dt=INITIAL velocityTherefore, The initial velocity: v=20t+7 m/s



Discussion

No Comment Found

Related InterviewSolutions