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The distance covered by a particle moving along a straight line path with uniform acceleration is given by x=6+7t+10t |
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Answer» ,DIFFERENTIATE the given EQUATION w.r.t. t(time)….dx/dt=0+7+(2×10)t^2-1dx/dt=20t+7since,dx/dt=INITIAL velocityTherefore, The initial velocity: v=20t+7 m/s |
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