The distance between the rails of the track is 1.67 m. How much the outer rail be elecated for curve of 0.5km radius, so that a train moving with speed 54kmh^(-1) can take safe turn on track.

The distance between the rails of the track is 1.67 m. How much the ou

1.	The distance between the rails of the track is 1.67 m. How much the outer rail be elecated for curve of 0.5km radius, so that a train moving with speed 54kmh^(-1) can take safe turn on track.
Answer» Explanation:Brainly.inWhat is your question?sumanmohapatra2003Secondary SCHOOL Physics 8+4 ptsA train has to negotiate a curve of 400m by how much the outer rail be raised with respect to inner rail for speed 48km/hr. The distance between rails is 1m?REPORT by Taragarasha 27.09.2016Answer Radius of curved path is r. Width of path is b m. the outer edge is raised by H w.r.t inner edge so that a car with speed V can PASS safe over it. the value of h istanθ = v²/rg=h/bh=v ²b/rgsubstituting the values according to given question,v=48km/h =(48x 1000)/60x60m/s⇒40/3 m/sb=1mr=400mg=9.8m/s2h=(40/3)²x1/400x9.8⇒0.0045m⇒4.54cm

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The distance between the rails of the track is 1.67 m. How much the outer rail be elecated for curve of 0.5km radius, so that a train moving with speed 54kmh^(-1) can take safe turn on track.

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