1.

The distance between the parallel planes2x – 3y + 6z + 1 = 0 and4x – 6y + 12z - 5 = 0) is​

Answer» ONG>Answer:

2/1 UNITS

Step-by-step explanation:

2x−3y+6z+1=0

4x−6y+12z−5=0

implise2x−3y+6y− 5/2=0

Distance between the GIVEN PLANES

= (d1-d2)/√a²+b²+c²

=(1+5/2)/√4+9+36

= 2/1 units



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