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The distance between the parallel planes2x – 3y + 6z + 1 = 0 and4x – 6y + 12z - 5 = 0) is |
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Answer» ONG>Answer: 2/1 UNITS Step-by-step explanation: 2x−3y+6z+1=0 4x−6y+12z−5=0 implise2x−3y+6y− 5/2=0 Distance between the GIVEN PLANES = (d1-d2)/√a²+b²+c² =(1+5/2)/√4+9+36 = 2/1 units |
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