The distance between the cathode (filament) and the target in an X-ray – InterviewSolution

1.	The distance between the cathode (filament) and the target in an X-ray tube is 15 m. If the cut-off wavelength is 30 pm, find the electric field between the cathode and the target.(hc=1.24×10−6 eV)
Answer» The distance between the cathode (filament) and the target in an X-ray tube is $15 m$ . If the cut-off wavelength is $30 pm$ , find the electric field between the cathode and the target. $(h c = 1.24 \times 10^{- 6} eV)$

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