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The dissociation equilibrium of a gas `AB_(2)` can be represented as, `2AB_(2)(g)iff2AB(g)+B_(2)(g)`. The degree of dissociation is x and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant `k_(p)` and total pressure P is :A. `(k_(p))/(P)`B. `(2k_(p))/(P)`C. `((2k_(p))/(P))^(1//3)`D. `((2k_(p))/(P))^(1//2)` |
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Answer» Correct Answer - D `BeCl_(2) lt AlCl_(3) lt SiCl_(4)` `C Cl_(4)ltPCl_(5)ltPF_(5)` `Na^(+) lt Mg^(2+) lt Al^(3+)` |
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