1.

The dissociation constant of a weak monoacidic base is 10^-5. The pH of its 0.1 M solution will be approximately to to

Answer»

Hey there!

we know that ,

For a weak ACID, [H  +  ]= \sqrt{ka*c}

The dissociation constant is 10^  −5  and the concentration is 0.1 M.

Let us now substitute the VALUES in our formula :  

  • [H  +] =  \sqrt{(1* 10^-5) 0.1}

​           = \sqrt{1* 10^-6}    

                =  1 * 10^{-3}

  • pH = −log[H  +  ]

              = - log10 ^{-3}

              = -(-3)log_{10}

              =  3log_{10}

              = 3                      (log_{10} = 1)            

#Hope it helps!



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