The dissociation constant of 0.05 M CH3COOH is given as 1.8×10−5. T – InterviewSolution

1.	The dissociation constant of 0.05 M CH3COOH is given as 1.8×10−5. The percentage dissociation of CH3COOH in 0.2 M HCl solution is x×10−3%. Find the value of x.
Answer» The dissociation constant of $0.05 M C H_{3} C O O H$ is given as $1.8 \times 10^{- 5}$ . The percentage dissociation of $C H_{3} C O O H$ in $0.2 M H C l$ solution is $x \times 10^{- 3} %$ . Find the value of $x$ .

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