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The displacemwnt in m of a particle is given by x =18+5t² |
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Answer» using diffrentiation method x = 18t + 5t^2 dx / dt = 18 + 10t v = 18 + 10t t = 2 sec v = 18 + 10 * 2 = 18 + 20 = 38 m / sec t = 3 sec v = 18 + 10 * 3 = 18 + 20 = 48 m / s v(av) = 38 + 48/ 2 = 43 m/swc dv / dt = 10 a = 10 m/ s Read more on Brainly.in - brainly.in/question/537063#readmore |
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