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The displacement x of a particle varies with time t as x=-5t2+20t+30. Find the position,velocity , acceleration of the particle at t=0.when will the velocity of the particle become 0? |
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Answer» tion:Let US assume SI units are to be used position x = ( -5t² + 20t + 30 )Velocity dx/dt = (-5t + 20) m/sTo find acceration differentiate EQUATION of velocity w.r.t t,We get d^2 x/dt^2 = -5. Thus, acceleration = -5 m/s²Since acceleration is constant, this motion is uniformly accelerated motion.Velocity will become zero when t = 20/5 = 4 seconds.Now,Position = -5(4)² + 20(4) + 30 = -80 + 60 + 30 = 10 mTherefore,Position = 10 mVelocity will become 0 in 4 seconds.Acceleration = -5 m/s²Hope it helps! |
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