The displacement x of a particle at the instant when its velocity v is given by v = sqrt(3x +16). Find its acceleration and initial velocity

The displacement x of a particle at the instant when its velocity v is

1.	The displacement x of a particle at the instant when its velocity v is given by v = sqrt(3x +16). Find its acceleration and initial velocity
Answer» Solution :`v=sqrt(3x+16) or v^(2)=3x+16` `or v^(2)-16=3x` COMPARING with `v^(2)-U^(2)=2AS`. we get u=4 units, 2a=3 or a=1.5 units.