The displacement time relation for a particle can be expressed as, y = 0.5 [cos^2 (n pi t) - sin^2 (n pi t)] .The relation shows that:

The displacement time relation for a particle can be expressed as, y =

1.	The displacement time relation for a particle can be expressed as, y = 0.5 [cos^2 (n pi t) - sin^2 (n pi t)] .The relation shows that:
Answer» the particle is executing a SHM with amplitude 0.5 m the particle is executing a SHM with a frequency N TIMES that of a second's pendulum the particle is executing a SHM and the velocity in its mean position is `(3.142n)ms^(-1)` the particle is not executing a SHM at all Answer :A::C