The displacement-time relation for a particle can be expressed as, y = 5[cos^2 (4pit) - sin^2 (4 pi t)] . The relation shows that:

The displacement-time relation for a particle can be expressed as, y =

1.	The displacement-time relation for a particle can be expressed as, y = 5[cos^2 (4pit) - sin^2 (4 pi t)] . The relation shows that:
Answer» The PARTICLE is executing a SHM with amplitude 5 m The particle is executing a SHM with a frequency 4 times that of a second's pendulum The particle is executing a SHM and the velocity in its mean POSITION is (40)m/s the particle is not executing a SHM at all Answer :A::C