The displacement of a particle is given by x(t)= 4 t^2 +8 t m. Its vel

1.	The displacement of a particle is given by x(t)= 4 t^2 +8 t m. Its velocity at t = 5 s will be:-
Answer» Answer: x(t)= 4 t^2 + 8 t m VELOCITY at t =5 s will be: FORMULA of velocity = DISPLACEMENT/ time = d/dt ( 4t^2 + 8T ) = 8t + 8 now , put t = 5 s = 8(5) +8 ANS = 48 m

The displacement of a particle is given by x(t)= 4 t^2 +8 t m. Its velocity at t = 5 s will be:-

Answer»

Answer:

x(t)= 4 t^2 + 8 t m

VELOCITY at t =5 s will be:

FORMULA of velocity = DISPLACEMENT/ time

= d/dt ( 4t^2 + 8T )

= 8t + 8

now , put t = 5 s

= 8(5) +8

ANS = 48 m

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The displacement of a particle is given by x(t)= 4 t^2 +8 t m. Its velocity at t = 5 s will be:-

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