1.

The displacement of a particle is given by x=(t-2)^(2)where x is in meters and in seconds. The distance covered by the particle in first 4 seconds is :

Answer»

4m
8 m
12 m
16 m

Solution :Here the displacement at any time t is given by
`x=(t-2)^(2)`
Now whent=0
`x_0 =4 m`
This means the PARTICLE has an INITIAL displacement of 4 m.
The displacement in first 4 second with be
`x_4 =(4-2)^(2)=4m`
`:.` Total displacement in first 4 seconds will be
`x=x_0 +x_4 =8m`


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