The displacement of a particle executing SHM is given by x = 0.10 sin ((2pit)/(T)+phi)where all the quantities are in SI units. The time period of vibration is 3s. At t = 0, the particle is displaced by 0.05m. Findthe initial phase,

The displacement of a particle executing SHM is given by x = 0.10 sin

1.	The displacement of a particle executing SHM is given by x = 0.10 sin ((2pit)/(T)+phi)where all the quantities are in SI units. The time period of vibration is 3s. At t = 0, the particle is displaced by 0.05m. Findthe initial phase,
Answer» Solution :For the particle in SHM, the DISPLACEMENT , `x= 0.10sin((2pit)/(T)+PHI)` `= 0.10sin((2PI)/(3)t+phi)( :.T=3s)` At t=0, x= 0.05 `0.05 = 0.10 SIN((2pi)/(3) xx0+phi)= 0.10sinphi` `sinphi= (1)/(2) IMPLIES phi= (pi)/(6) "radian"` or `30^(@)`