The displacement of a particle executing SHM is given by x = 0.10 sin ((2pit)/(T)+phi)where all the quantities are in SI units. The time period of vibration is 3s. At t = 0, the particle is displaced by 0.05m. Findthe phase difference between any two positions of the particle 2 s apart.

The displacement of a particle executing SHM is given by x = 0.10 sin

1.	The displacement of a particle executing SHM is given by x = 0.10 sin ((2pit)/(T)+phi)where all the quantities are in SI units. The time period of vibration is 3s. At t = 0, the particle is displaced by 0.05m. Findthe phase difference between any two positions of the particle 2 s apart.
Answer» Solution :For the particle in SHM, the displacement , `x= 0.10sin((2pit)/(T)+phi)` `= 0.10sin((2PI)/(3)t+phi)( :.T=3s)` Phase angle at `t= t_(1)` is `phi_(1)= ((2pi)/(3)xxt_(1)+phi)`and `t= t_(2)` is `phi_(2)= ((2pi)/(3)xxt_(2)+phi)` Phase difference `= phi_(2)-phi_(1)` `=((2pi)/(3)t_(2)+phi)- ((2pi)/(3)t_(1)+phi)= (2pi)/(3)(t_(2)-t_(1))` `= (2pi)/(3) xx 2= (4PI)/(3) "RADIAN" ( :. t_(2)-t_(1)=2)`