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The displacement of a particle executing S.H.M. is given by `y = 10 sin [6t + (pi)/(3)]` where y is in metres and t is in seconds. Then the initial displacement and velocity of the particle isA. `5sqrt3 m and 30 ms^(-1)`B. `15 m and 5 sqrt3 ms^(-1)`C. `15 sqrt3 and 30 ms^(-1)`D. `20 sqrt3 and 30 ms^(-1)` |
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Answer» Correct Answer - A `y = 10 sin [6t + (pi)/(3)]` `y = 10 sin [6 xx 0 + (pi)/(3)]` `= 10 xx (sqrt3)/(2) = 5 sqrt3` `v = (dv)/(dt) = 10 xx 6 xx cos (6t + (pi)/(3))` `v = 60 xx cos (0 + (pi)/(3))` `= 60 xx (1)/(2) = 30 m//s` |
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