The displacement (in m) of a particle of mass 100 gm from its mean position is given by the equation Y=0.05 sin 3pi(5t +0.4)

The displacement (in m) of a particle of mass 100 gm from its mean pos

1.	The displacement (in m) of a particle of mass 100 gm from its mean position is given by the equation Y=0.05 sin 3pi(5t +0.4)
Answer» the TIME period of motion is 1/30 sec. the time period of motion is 1/7.5 sec . the MAXIMUM ACCELERATION of the particle is `11.251pi^2 m//s^2` the force acting on the particle is ZERO when the displacement is 0.05 m Answer :B::C