The disc of mass M with uniform surface mass density σ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the position (x3Rπ,x3Rπ), then, x is _______.(Round off to the nearest integer)(R is the radius of disc)

The disc of mass M with uniform surface mass density σ is shown in th

1.	The disc of mass M with uniform surface mass density σ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the position (x3Rπ,x3Rπ), then, x is _______.(Round off to the nearest integer)(R is the radius of disc)
Answer» The disc of mass $M$ with uniform surface mass density $σ$ is shown in the figure. The centre of mass of the quarter disc $($ the shaded area $)$ is at the position $(\frac{x}{3} \frac{R}{π}, \frac{x}{3} \frac{R}{π})$ , then, $x$ is _______. $($ Round off to the nearest integer $)$ $(R$ is the radius of disc $)$

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The disc of mass M with uniform surface mass density σ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the position (x3Rπ,x3Rπ), then, x is _______.(Round off to the nearest integer)(R is the radius of disc)

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