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The dipole moment of LiH is ` 1.964xx10^(-29)` Cm and the interatomic distance between Li and H in the molecule is ` 1 .596Å` . Calualate the persent ionic character of the molecule . |
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Answer» The dipole molecule were 100% ionic , `mu_("ionic")= q xx d = (1 .602 xx10^(-19)C) xx(1.596 xx10^(-10)m) = 2. 557xx 10^(-29) ` cm `mu_("observed ")=1 .964 xx10^(-29) ` cm (Given) `therefore % "ionic character"= (mu_("observed "))/(mu_("ionic")) xx100 = (1 .964 xx10^(-29))/ (2. 557xx 10^(-29) cm )xx100 = 76.81 %`. |
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