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the dipole moment of HBr is 2.60×1030 Cm the interatomic distanve is 141pm what is the percentage ionic chatacter of HBr |
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Answer» dipole moment =charge X DISTANCE between them =1.6 x 10^-19 x 141 x 10^-12 Cm =225.6 x 10^-31 Cm =22.56 x 10^-30 Cm now, % of IONIC characters =dipole moment by experimental x 100/dipole moment by THEORETICAL =(2.6 x 10^-30/22.56 x 10^-30 ) x 100 =260/22.56 % =11.52 % READ more on Brainly.in - brainly.in/question/1105804#readmore |
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