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The diode used at a constant potential drop of 0.5 V at all currents and maximum power rating of 100 mW. What resistance must be connected in series diode, so that current in circuit is maximum? A. `200 Omega`B. `6.67 Omega`C. `5 Omega`D. `15 Omega`

Answer» Correct Answer - C
Current passing in the circuit is
`I=P/V = (100 xx 10^(-3))/0.5 = 0.2 A`
Value of connected series resistance,
`R= (1.5 -0.5)/0.2 rArr R=1/0.2`
`therefore R=5Omega`


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