The dimensions of mu_(0)I//MB where mu_(0) is the permeability of free space, I is the moment of inertia, M is the magnetic moment and B is the magnetic induction respectively, are those of

The dimensions of mu_(0)I//MB where mu_(0) is the permeability of free

1.	The dimensions of mu_(0)I//MB where mu_(0) is the permeability of free space, I is the moment of inertia, M is the magnetic moment and B is the magnetic induction respectively, are those of
Answer» time `("time")^(2)` `("time")^(3)` `("time")^((1)/(2))` Solution :`B= mu_(0)ni` (For a solenoid) where n is the number of turns per unit length , I is the current and `mu_(0)` is the permeability of free space. or `(mu_(0))/(B) = (1)/(ni) :. [(mu_(0))/(B)]= [(1)/(ni)]= (1)/([L^(-1)][A])= [LA^(-1)]` `[M]= ["MAGNETIC moment"]= [ m xx 2L]` [pole strenght `xx` magnetic lenght] `=["weber xx L] = [ML^(2)T^(-2)A^(-1)xx L]= [ML^(3)T^(-2)A^(-1)]` `= [LA^(-1)] xx ([ML^(2)])/([ML^(3)T^(-2)A^(-1)])= [T^(2)]= ("time")^(2)`