The dimensions of (l)/(KA) are (l is the length of rod, K is the thermal conductivity of rod and A is the area of cross-section of rod)

The dimensions of (l)/(KA) are (l is the length of rod, K is the therm

1.	The dimensions of (l)/(KA) are (l is the length of rod, K is the thermal conductivity of rod and A is the area of cross-section of rod)
Answer» `[ML^(2)T^(-3)K^(-1)]` `[M^(-1)L^(-2)T^(3)K]` `[ML^(2)T^(-3)K^(-2)]` `[MLT^(-3)K^(-1)]` Solution :Rate of heat flow `(DQ)/(dt)= (Kad theta)/(l)` or `(l)/(KA)= (d theta)/(dQ//dt) :. [(l)/(KA)]= [(K)/(ML^(2)T^(-3))]= [M^(-1)L^(-2)T^(3)K]`