1.

The dimensions of Hubble's constant are :

Answer»

`[M^(0)L^(0)T]`
`[M^(0)L^(0)T^(-1)]`
`[MLT^(2)]`
`[MLT^(-1)]`

Solution :`"HUBBLE's constant"=("Velocity")/("Distance")`
`=([LT^(-1)])/([L])=T^(-1)`
`=M^(0)L^(0)T^(-1)`


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