| 1. |
The dimensions of a room are in the ratio 3:2:1 and its total surface area is 352m²? Find the dimensions of the room ? |
|
Answer» Answer: The answer is -
Step-by-step explanation: To find the dimensions of the room The dimensions are in the RATIO 3:2:1 and its total surface area is 352 m^2(given) Step 1 = First LET the dimensions be 3x[l], 2x[B] and x[h](or 1x) respectively As we know that whenever there are three different dimensions of a room it is considered a cuboid And we know that total surface area of a cuboid is Where l = length, b = breadth, h = height 2(lb + bh + lh) We know that l = 3x, b = 2x and h = x = 2[(3x)(2x) + (2x)(x) + (3x)(x)] = 2[6x^2 + 2x^2 + 3x^2] = 12x^2 + 4x^2 + 6x^2(L.H.S) Step 2 = Equate the L.H.S[12x^2 + 4x^2 + 6x^2] with R.H.S[352 m^2] That is, L.H.S = R.H.S 12x^2 + 4x^2 + 6x^2 = 352 Add the like terms 22x^2 = 352 x^2 = 352/22 = 16 x = 4 The dimensions are as follows-
|
|