1.

THE DIMENSIONS OF A RECTANGLE ARE 48 CM AND 14 CM. FIND THE LENGTH OF THE DIAGONAL OF THE RECTANGLE​

Answer»

GIVEN:

  • Length of the rectangle = 48 cm
  • Breadth of the rectangle = 14 cm

TO FIND:

  • What is the length of the diagonal of the rectangle ?

SOLUTION:

Let the diagonal of the rectangle be 'x' cm

We know that the formula for finding the diagonal of rectangle is:-

\large{\boxed{\bf{\star \: (DIAGONAL)^2 = (BASE)^2 + (<klux>PERPENDICULAR</klux>)^2 \: \star}}}

According to question:-

  • Perpendicular = 14 cm
  • Base = 48 cm

On putting the given VALUES in the formula, we get

\sf{\longmapsto (x)^2 = (48)^2 + (14)^2 }

\sf{\longmapsto x^2 = 2304 + 196 }

\sf{\longmapsto x^2 = 2500}

\sf{\longmapsto x = \sqrt{2500} }

\bf{\longmapsto x = <klux>50</klux> \: cm }

  • DIAGONAL = x = 50 cm

Hence, the diagonal of the rectangle is 50 cm

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