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| 1. |
The dimensions of `1/2 epsilon_(0)E^(2) (epsilon_(0)=` permittivity of free space, `E=` electric field) is |
| Answer» `[epsilon_(0) E^(2)]=[("Energy")/("Volume")]=(ML^(2)T^(-2))/(L^(3))=ML^(-1)T^(-2)` | |