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The digit at tens place of a two-digit number is three times the digit at ones place. If the sum of this number and the number formed by reversing its digits is 88, find the number. |
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Answer» let x = the 10's digitlet y = the unitsthen10x+y = the number:Write an equation for each statement::" the digit at the tens place of a two digit number is three times the digit at ones place."x = 3y:"The sum of this number and the number formed by reversing its digit is 88,"(10x + y) + (10y + x) = 8810x + x + 10y + y = 8811x + 11y = 88simplify, divide by 11x + y = 8:(Replace x with 3y)3y+y=84y=8y=2x+y=8x+2=8x=6 That is the solution. |
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