The difference of two numbers is 14 and their sum is 40.find out the p

1.	The difference of two numbers is 14 and their sum is 40.find out the product of the numbers
Answer» GIVEN: • The difference of two numbers is 14. • Their SUM is 40. To calculate: • The product of the numbers. Calculation: LET, First number = x Second number = y According to the question, $\longrightarrow \bf \red {x - y = 14 }$ [ Since, the difference of two numbers is 14. ] From this equation, $\longrightarrow \sf {x = 14 +y}$ (By transposition.). . . . . . . (Equation 1) Also, $\longrightarrow \bf \red{x + y = 40}$ Now, from this equation we'll find the value of x and y. $\longrightarrow \sf {(14+y) + y= 40 }$ Substituting the value of x from equation (I). $\longrightarrow \sf {14+y+ y= 40 }$ $\longrightarrow \sf {14+2y= 40 }$ $\longrightarrow \sf {2y= 40-14 }$ $\longrightarrow \sf {2y= 26 }$ $\longrightarrow \sf {y=\dfrac{26}{2} }$ $\longrightarrow\fbox{ \sf {y= 13 }}$ Henceforth, Second number (y) = 13 And, → First number (x) = 14 + y [ From equation 1] → x = 14 + 13 → x = 27 First number (x) = 27 ~Calculating their product: $\longrightarrow\boxed{ \sf { Product = First \: Number \times Second \: Number }}$ $\longrightarrow \sf {Product = xy }$ $\longrightarrow \sf {Product = 13 \times 27 }$ $\longrightarrow\fbox{ \sf\red {Product = 351}}$ THEREFORE, the product of the numbers is 351.