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The difference of two natural numbers is 3 and the difference of their reciprocals is 3 / 28. Find the numbers.Quadratic EquationsClass 10

Answer»

So LET the LARGER one be X and ANOTHER be y
x-y=3
X=3+y
now
1/X -1/y = 3/28
1/3+y -1/y =3/28
y-3-y/y^2+3y=3/28
3y^2+9y+84=0
y^2+3y+28=0
y^2+7y-4y+28=0
y(y+7)-4(y+7)=0
(y+7)(y-4)=0
y=-7 or 4
negative VALUE DISCARD as natural no. is given
so smaller no. is 4
and larger no. is 3+4=7


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