1.

The difference of the squares of two positive numbers is 45. The square of thesmaller number is four times the larger number. Find the numbers​

Answer»

Answer:

Given :

  • The DIFFERENCE of the squares of two POSITIVE numbers is 45
  • The square of the smaller number is four TIMES the larger number

To find :

  • Numbers

Solution :

  • Let the larger number be x
  • Let the smaller number be y

Given that , The differences of the squares of two positive numbers is 45 then ,

  • x² + y² = 45 is eq (1)

And also , the square of the smaller number is four times the larger number then

  • y² = 4x is eq(2)

According to Question, From eq (1) and eq (2) we get ,

》x² + y² = 45 + y² = 4x

》x² - 4x = 45

》x² - 4x - 45 = 0

》x² - (9 - 5) x - 45 = 0

Now by using factorization method we get,

》x² - 9x + 5x - 45 = 0

》x(x - 9) + 5(x - 9) = 0

》(x - 9) (x + 5) = 0

》x - 9 = 0 or x + 5 = 0

》x = - 9 , x = - 5

》x = 9

Now , putting the value in eq (2) we get,

》y² = 4x

》y² = 4(9)

》y² = 36

》 y = √36

》y = 6

Hence , 9 and 6 are the numbers



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