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The difference of the squares of two positive numbers is 45. The square of thesmaller number is four times the larger number. Find the numbers |
Answer» Answer:
Given :
To find :
Solution :
Given that , The differences of the squares of two positive numbers is 45 then ,
And also , the square of the smaller number is four times the larger number then
According to Question, From eq (1) and eq (2) we get , 》x² + y² = 45 + y² = 4x 》x² - 4x = 45 》x² - 4x - 45 = 0 》x² - (9 - 5) x - 45 = 0 Now by using factorization method we get, 》x² - 9x + 5x - 45 = 0 》x(x - 9) + 5(x - 9) = 0 》(x - 9) (x + 5) = 0 》x - 9 = 0 or x + 5 = 0 》x = - 9 , x = - 5 》x = 9 Now , putting the value in eq (2) we get, 》y² = 4x 》y² = 4(9) 》y² = 36 》 y = √36 》y = 6 Hence , 9 and 6 are the numbers |
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