the difference between the ages of two sisters is 10 years. Fifteen ye

1.	the difference between the ages of two sisters is 10 years. Fifteen years ago their ages were in the ratio 2:1. find the ratio of their ages 15years hence
Answer» Given : DIFFERENCE between the ages of two SISTERS is 10 YEARS . 15 years AGO their ages were in the artio 2:1 . To Find : Ratio of their ages after 15 years . Solution : $\longmapsto\tt{Let\:the\:Age\:of\:sister\:A=x}$ $\longmapsto\tt{Age\:of\:sister\:B=x+10}$ Before 15 years : $\longmapsto\tt{Age\:of\:Sister\:A=x-15}$ $\longmapsto\tt{Age\:of\:Sister\:B=x+10-15=x-5}$ A.T.Q : $\longmapsto\tt{\dfrac{x-5}{x-15}=\dfrac{2}{1}}$ $\longmapsto\tt{1(x-5)=2(x-15)}$ $\longmapsto\tt{x-5=2x-30}$ $\longmapsto\tt{x-2x=-30+5}$ $\longmapsto\tt{-x=-25}$ $\longmapsto\tt\bf{x=25}$ Value of x is 25 .. Therefore : $\longmapsto\tt{Present\:Age\:of\:Sister\:A=x}$ $\longmapsto\tt\bf{25\:yrs}$ $\longmapsto\tt{Present\:Age\:of\:Sister\:B=25+10}$ $\longmapsto\tt\bf{35\:yrs}$ Now , After 15 years : $\longmapsto\tt{Age\:of\:Sister\:A=25+15}$ $\longmapsto\tt\bf{40\:yrs}$ $\longmapsto\tt{Age\:of\:Sister\:B=35+15}$ $\longmapsto\tt\bf{50\:yrs}$ Ratio : $\longmapsto\tt{\dfrac{5{\not{0}}}{4{\not{0}}}}$ $\longmapsto\tt\bf{\dfrac{5}{4}}$ So , The Ratio is 5:4 ...