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The difference between nth and n+1th bohr orbits of h atom is equal to its |
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Answer» Explanation: r_n=\frac{n^2\times 52.9}{Z} (in pm) where, r_n = radius of n^{th} orbit n = number of orbit Z = ATOMIC number of HYDROGEN = 1 r_n-r_{n+1}=r_{n-1} \frac{(n+1)^2\times 52.9}{Z}-(\frac{(n)^2\times 52.9}{Z})=\frac{(n-1)^2\times 52.9}{Z} (n+1)^2-(n)^2=(n-1)^2 n = 4 |
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