1.

The difference between nth and n+1th bohr orbits of h atom is equal to its

Answer»

Explanation:

r_n=\frac{n^2\times 52.9}{Z} (in pm)

where,

r_n = radius of n^{th} orbit

n = number of orbit

Z = ATOMIC number of HYDROGEN = 1

r_n-r_{n+1}=r_{n-1}

\frac{(n+1)^2\times 52.9}{Z}-(\frac{(n)^2\times 52.9}{Z})=\frac{(n-1)^2\times 52.9}{Z}

(n+1)^2-(n)^2=(n-1)^2

n = 4



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