The diameter of zinc atom is 2.6 Å. Calculate (a) radius of zinc ato

1.	The diameter of zinc atom is 2.6 Å. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm, if the zinc atoms are arranged side by side lengthwise.
Answer» (a) 1 Å = 10² pm Therefore 2.6 Å = 2.6 x 10² pm = 260 pm (b) Length of the scale = 1.6 cm = 1.6 x 10¹⁰pm Diameter of zinc atom = 260 pm No. of zinc atoms placed side by side = {(1.6 x 10¹⁰ pm)}/{(260 pm)} = 6.154 x 10⁷

The diameter of zinc atom is 2.6 Å. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm, if the zinc atoms are arranged side by side lengthwise.

Answer»

(a) 1 Å = 10² pm

Therefore 2.6 Å = 2.6 x 10² pm = 260 pm

(b) Length of the scale = 1.6 cm = 1.6 x 10¹⁰pm

Diameter of zinc atom = 260 pm

No. of zinc atoms placed side by side = {(1.6 x 10¹⁰ pm)}/{(260 pm)} = 6.154 x 10⁷