The diameter of a cycle wheel is 1.4 m. Find the distance covered by t

1.	The diameter of a cycle wheel is 1.4 m. Find the distance covered by the cycle in making 300 revolutions by its wheels (Take )
Answer» $\underline{ \underline{ \sf \red{Question}}} \red:$ The DIAMETER of a CYCLE wheel is 1.4 m. FIND the distance covered by the cycle in making 300 revolutions by its WHEELS (Take $\pi = \dfrac{22}{7}$ ) $\underline{ \underline{ \sf \red{Answer}}} \red:$ $\rm{Radius \: of \: the \: wheel \: = \bigg( \dfrac{1}{2} \times 1.4 \bigg)m}$ $\implies \rm r = \bigg( \dfrac{1}{2} \times 1.4 \times 100 \bigg)cm$ $\implies \rm r = 70 \: cm$ $\rm Circumference \: of \: the \: wheel \: = 2 \pi r = \bigg(2 \times \dfrac{22}{7} \times 70 \bigg) \: cm$ $\implies \rm circumference \: = 440 \: cm$ $\rm Distance \: covered \: by \: the \: wheel \: in \: 1 \: revolution \: = 440 \: cm$ $\rm Distance \: covered \: by \: the \: wheel \: in \: 300 \: revolutions \: = \bigg( \dfrac{400 \times 300}{100} \bigg)m$ $\implies \rm 1320 \: m$ $\therefore \rm Distance \: covered \: by \: the \: cycle \: = 1320 \: m$

The diameter of a cycle wheel is 1.4 m. Find the distance covered by the cycle in making 300 revolutions by its wheels (Take )

Answer»

$\underline{ \underline{ \sf \red{Question}}} \red:$

The DIAMETER of a CYCLE wheel is 1.4 m. FIND the distance covered by the cycle in making 300 revolutions by its WHEELS (Take $\pi = \dfrac{22}{7}$ )

$\underline{ \underline{ \sf \red{Answer}}} \red:$

$\rm{Radius \: of \: the \: wheel \: = \bigg( \dfrac{1}{2} \times 1.4 \bigg)m}$

$\implies \rm r = \bigg( \dfrac{1}{2} \times 1.4 \times 100 \bigg)cm$

$\implies \rm r = 70 \: cm$

$\rm Circumference \: of \: the \: wheel \: = 2 \pi r = \bigg(2 \times \dfrac{22}{7} \times 70 \bigg) \: cm$

$\implies \rm circumference \: = 440 \: cm$

$\rm Distance \: covered \: by \: the \: wheel \: in \: 1 \: revolution \: = 440 \: cm$

$\rm Distance \: covered \: by \: the \: wheel \: in \: 300 \: revolutions \: = \bigg( \dfrac{400 \times 300}{100} \bigg)m$

$\implies \rm 1320 \: m$

$\therefore \rm Distance \: covered \: by \: the \: cycle \: = 1320 \: m$