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The diagram shows a semicircular ring carrying uniformly distributed charge +2muC on it. The radius of the ring is 4 cm A point charge +2muC is taken slowly from the point (0,0,8cm) to (0,8cm,0). The manitude of work done is equal to 4J After fixing the charge at its new position, the ring is rotated in anticlockwise sense about the x-axis as seen from (16cm,0,0)by an angle pi//2What is the magnitude of work done by electric field during the rotation of the ring? |
Answer»  `W=U_(B)-Q^(2)/((4piin_(0)sqrt(5))R)` …..(1) At new position `U'_(B)=Q^(2)/((4piin_(0)sqrt(5))R)` Work DONE `=U'_(B)=U_(B)=-W=-4J` |
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