The diagonals AC and BD of parallelogram ABCD intersect at the point o

1.	The diagonals AC and BD of parallelogram ABCD intersect at the point o. If __DAC = 34 and ZAOB= 75 then measure _DBC is3401750
Answer» ong>Answer: ∠DBC = 41° Step-by-step explanation: ABCD is a parallelogram . ∴ AD \| \| BC ⇒ ∠ACB = ∠DAC = 34° Now, ∠AOB is an exterior ANGLE of △BOC ∴ ∠OBC + OCB = ∠AOB [ EXT ∠ = SUM of two int. opp. ∠S] ⇒ ∠OBC + 34° = 75° ⇒ ∠OBC = 75° - 34° = 41° or ∠DBC = 41°

The diagonals AC and BD of parallelogram ABCD intersect at the point o. If __DAC = 34 and ZAOB= 75 then measure _DBC is3401750

Answer»

ong>Answer:

∠DBC = 41°

Step-by-step explanation:

ABCD is a parallelogram .

∴ AD | | BC ⇒ ∠ACB = ∠DAC = 34°

Now, ∠AOB is an exterior ANGLE of △BOC

∴ ∠OBC + OCB = ∠AOB [ EXT ∠ = SUM of two int. opp. ∠S]

⇒ ∠OBC + 34° = 75°

⇒ ∠OBC = 75° - 34° = 41°

or ∠DBC = 41°