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The diagonals AC and BD of aparallelogram ABCD intersect each other atthe point o. If CAD = 32° and AOB = 70°,find DBC. |
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Answer» Quadrilateral ABCD is a parallelogram. So, AD ∣∣ BC ∴ ∠DAC = ∠ACB --- ( ALTERNATE angle) ∴ ∠ACB = 32 ∘
∠AOB + ∠BOC = 180 ∘ --- (straight angle) ⇒70 ∘ + ∠BOC = 180 ∘
∴ ∠BOC = 110 ∘
In △BOC, ∠OBC + ∠BOC + ∠OCB = 180 ∘
⇒∠OBC + 110 ∘ + 32 ∘ = 180 ∘
⇒ ∠OBC = 38 ∘
∴ ∠DBC = 38 ∘ |
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