The diagonals AC and BD OF A RHOMBUS ABCD meet at O if AC = 8CM, BD =

1.	The diagonals AC and BD OF A RHOMBUS ABCD meet at O if AC = 8CM, BD = 6CM . Find sin angle OCD
Answer» Answer: Diagonals of a Rhombus perpendicularlly bisect each other => AO = OC = AC/2 = 8/2 = 4 cm Similalrly BO = OD = BD/2 = 6/2 = 3 Cm in Δ OCD OC = 4 cm OD = 3 cm CD² = OC² + OD² => CD² = 4² + 3² => CD² = 25 => CD = 5 cm sin ∠OCD = OD/CD => Sin∠OCD = 3/5 Step-by-step explanation: Hope this HELPS you

The diagonals AC and BD OF A RHOMBUS ABCD meet at O if AC = 8CM, BD = 6CM . Find sin angle OCD

Answer»

Answer:

Diagonals of a Rhombus perpendicularlly bisect each other

=> AO = OC = AC/2 = 8/2 = 4 cm

Similalrly

BO = OD = BD/2 = 6/2 = 3 Cm

in Δ OCD

OC = 4 cm

OD = 3 cm

CD² = OC² + OD²

=> CD² = 4² + 3²

=> CD² = 25

=> CD = 5 cm

sin ∠OCD = OD/CD

=> Sin∠OCD = 3/5

Step-by-step explanation:

Hope this HELPS you

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The diagonals AC and BD OF A RHOMBUS ABCD meet at O if AC = 8CM, BD = 6CM . Find sin angle OCD

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